WoodPro WS-TS-1500 Owner's Manual - page 32
This stove has been tested for and must be installed on a
ƀQQT protector with the proper Thermal Resistance or R-value
as stated in step 1 of the installation instructions under “Locating Stove” section of this manual. If the
ƀQQT protector ma-
terials listed in the instructions are not available, materials with an equivalent R-value may be substituted.
Alternate materials may be rated with C-factor (Thermal Conductance) or k-factor (Thermal Conductivity) ratings
which must be converted to R-value to determine if the alternate material meets the tested requirements. The following
instructions provide the proper information and formulas for conversion to R-value.
To determine if alternate materials are acceptable follow this sequence.
1.
Conv
GTVOCVGTKCNURGEKſECVKQPUVQ4value:
a. R-value given — no conversion necessary
b. K-factor is given with a required thickness (T) in inches:
R = 1/k x T
c. C-factor is given: R = 1/C
2.
Determine the R-v
CNWGQHRTQRQUGFCNVGTPCVGƀQQTRTQVector:
a. Use formulas in step 1 above to calculate R-value of proposed material(s).
b. For multiple layers, add R-values of each layer to determine overall R-value.
3.
If the overall R-value of the
ƀQQT protector system is equal to or greater than the ƀQQT protector URGEKſECVKQPU given,
the alternate is acceptable.
&GſPKVKQPU
Thermal conductance(C) =
BTU
=
W
(hr)(ft
2
)(°F)
(m
2
)(°K)
Thermal conductivity (k) =
(Btu)(inch)
=
W
=
Btu
(hr)(ft
2
)(°F)
(m)(°K)
(hr)(ft)(°F)
Thermal resistance (R) =
(ft
2
)(hr)(°F)
=
(m
2
)(°K)
Btu
W
Example:
6JGURGEUQHƀQQTRTQVGEVQTOCVGTKCNUJQWNFDGKPEJVJKck material with a k-fCEVQTQH
The proposed alternativ
GOCVGTKCNKUŒDTKEMYKVJC%factor of 1.25 over 1/8-inch mineral board
with a k-factor of 0.29.
Step 1: Convert specs to R-value.
R = 1/k x
6Z5[UVGOOWUVJave a R-value of 0.893 = Rspecs
Step 2: Calculate R-value of individual components
Œ$TKEMYKVJ%factor = 1.25. R = 1/C = 1/1.25 = 0.80 = Rbrick
1/8-inch (0.125”) mineral board with k-factor = 0.2
4Z4OKPDTF
Step 3: Add R-values of components to get total R-value of system
4DTKEM 4OKPDTF 4U[stem
5VGR%QORCTG4U[UVGOVQ4URGEU
R s y s t e m = 1 . 2 3 1 i s l a rg e r t h a n R s p e c s o f 0 . 8 9 3 . S y s t e m R - va l u e ex c e e d s
t h e r e q u i r e d
URGEKſECVKQPUCPFVJGTGHQTGKUCPCEEGRVCDNGCNVGTnative.
FLOOR PROTECTOR MATERIAL CALCULATIONS
32